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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > Suppose refractive index muon is given as muon = A + B/lemda^2 where A and B are constants and lemda is wavelength, then dimensions of B are same as that of a. Wavelength b. volume

Suppose refractive index muon is given as muon = A + B/lemda^2 where A and B are constants and lemda is wavelength, then dimensions of B are same as that of a. Wavelength b. volume

Suppose refractive index muon is given as muon = A + B/lemda^2 where A and B are constants and lemda is wavelength then dimensions of B are same as that of a. Wavelength b. volume