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Sahay Sir > Question Answers > NEET Last 32 Years Solved 1988 - 2019 Physics and Chemistry Video Solutions > Physics > Chapter 17 - Thermal Properties of Matter > Steam at 100°C is passed into 20 g of water at 10°C. When water acquires a temperature of 80°C, the mass of water present will be [Take specific heat of water = 1 cal g^-1°C^-1 and latent heat of steam = 540 cal g^-1]

Steam at 100°C is passed into 20 g of water at 10°C. When water acquires a temperature of 80°C, the mass of water present will be [Take specific heat of water = 1 cal g^-1°C^-1 and latent heat of steam = 540 cal g^-1]

Steam at 100°C is passed into 20 g of water at 10°C. When water acquires a temperature of 80°C the mass of water present will be [Take specific heat of water = 1 cal g^-1°C^-1 and latent heat of steam = 540 cal g^-1]