Question Answers

Sahay Sir > Question Answers > Cengage JEE Mains Physics by B.M Sharma > Chapter 12 - Fluid Mechanics, Surface Tension and Viscosity > Statement I: When a body floats such that its parts are immersed into two immiscible liquids, then force exerted by liquid 1 is of magnitude ρ1v1g. Statement II: Total buoyant force = ρ1v1g + ρ2v2g.

Statement I: When a body floats such that its parts are immersed into two immiscible liquids, then force exerted by liquid 1 is of magnitude ρ1v1g. Statement II: Total buoyant force = ρ1v1g + ρ2v2g.

Statement I: When a body floats such that its parts are immersed into two immiscible liquids then force exerted by liquid 1 is of magnitude ρ1v1g. Statement II: Total buoyant force = ρ1v1g + ρ2v2g.