Show that 230 U 92 does not decay by emitting a neutron or proton. Given: M (229 U 92) =230.033927 amu, M(230 U 92) =229.033496 amu, M(229 Pa 91) = 229.032089 amu, m(n) = 1.008665 amu, m(p) = 1.007825 amu. M(229 Pa 91) = 229.032089 amu M(230 U 92) =229.033496 amu m(n) = 1.008665 amu m(p) = 1.007825 amu. Show that 230 U 92 does not decay by emitting a neutron or proton. Given: M (229 U 92) =230.033927 amu September 12, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) , Facebook Messenger WhatsApp Share this:TwitterFacebook Related