Reduction of acetyl chloride with H2 in presence of Pd gives (a) CH3COCH3 (b) C2H5OH (c) CH3COOH (d) CH3CHO Reduction of acetyl chloride with H2 in presence of Pd gives (a) CH3COCH3 (b) C2H5OH (c) CH3COOH (d) CH3CHO February 8, 2021 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) , Facebook Messenger WhatsApp Share this:TwitterFacebook Related