Rate of heat flow through a cylindrical rod is H1. Temperatures of ends of rod are T1 and T2. If all the dimensions of rod become double and temperature difference remains same and rate of heat flow becomes H2. Then conductivity K1 and K2 and areas of cross section (A1 and A2) and both having temperature (T1 and T2) at their ends. If the rate of heat loss due to conduction are equal Consider two rods of same length and different specific heats (s1 and s2) then August 26, 2020 Category: Chapter 17 - Thermal Properties of Matter , NEET Last 32 Years Solved 1988 - 2019 Physics and Chemistry Video Solutions , Physics , Facebook Messenger WhatsApp Share this:TwitterFacebook Related