Propene when heated with chlorine at about 500 C forms (a) CH2Cl.CH = CH2 (b) CH3.CHCl.CH2Cl (c) CH2Cl.CHCl.CH2Cl (d) All of these Propene when heated with chlorine at about 500 C forms (a) CH2Cl.CH = CH2 (b) CH3.CHCl.CH2Cl (c) CH2Cl.CHCl.CH2Cl (d) All of these December 13, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) , Facebook Messenger WhatsApp Share this:TwitterFacebook Related