Pb + Conc. HNO3 gives (a) Pb(NO3)2 + NO2 (b) PbNO3 + NO (c) Pb(NO3)4 + NO3 (d) Pb(N)3)3 + N2O Pb + Conc. HNO3 gives (a) Pb(NO3)2 + NO2 (b) PbNO3 + NO (c) Pb(NO3)4 + NO3 (d) Pb(N)3)3 + N2O November 17, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) , Facebook Messenger WhatsApp Share this:TwitterFacebook Related
