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Sahay Sir > Question Answers > Cengage JEE Mains Physics by B.M Sharma > Chapter 14 - KTG and Thermodynamics > One mole of a diatomic gas undergoes a process P = P0/ (1 + (V/V0)^3) where P0 and V0 are constants. The translational kinetic energy of the gas when V = V0 is given by

One mole of a diatomic gas undergoes a process P = P0/ (1 + (V/V0)^3) where P0 and V0 are constants. The translational kinetic energy of the gas when V = V0 is given by

One mole of a diatomic gas undergoes a process P = P0/ (1 + (V/V0)^3) where P0 and V0 are constants. The translational kinetic energy of the gas when V = V0 is given by