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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > One end of rod of length L and cross-sectional area A is kept in a funrance of temperature T1. The other end of the rod is kept at at temperature T2. The thermal conductivity of the material of the rod is K and emissivity of the rod is e. It is given that T2 = TS+ΔT where ΔT<<TS, TS being the temperature of the surroundings.

One end of rod of length L and cross-sectional area A is kept in a funrance of temperature T1. The other end of the rod is kept at at temperature T2. The thermal conductivity of the material of the rod is K and emissivity of the rod is e. It is given that T2 = TS+ΔT where ΔT<<TS, TS being the temperature of the surroundings.

A body cools in a cold surrounding obeying Newton's law of cooling. It is found that from t = 0 to t = t1 A cylindrical rod of heat capacity 120J/K in a room temperature 27C is heated internally by heater of power 250W from t = t1 will it loose one fourth the total heat? it loses half the total heat. In what time