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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > Light of wavelengthlambda = 500 nm falls on two narrow slits placed a distance d = 50 xx 10^-4 cm apart, at an angle phi= 30^@ relative to the slits as shown in figure. On the lower slit a transparent slab of thickness 0.1 mm and refractive index 3/2 is placed. The interference pattern is observed at a distance D=2m from the slits. Then, calculate

Light of wavelengthlambda = 500 nm falls on two narrow slits placed a distance d = 50 xx 10^-4 cm apart, at an angle phi= 30^@ relative to the slits as shown in figure. On the lower slit a transparent slab of thickness 0.1 mm and refractive index 3/2 is placed. The interference pattern is observed at a distance D=2m from the slits. Then, calculate

An object is placed at a distance of 20cm from a equi-concave lens of focal length 30cm find the position and nature of the image. Light of wavelengthlambda = 500 nm falls on two narrow slits placed a distance d = 50 xx 10^-4 cm apart whose one surface is silvered. If the radius of curvature of the silvered surface is 60cm