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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > Let current i=2A be flowing in each part of a wire frame as shown in Fig. 1.138. The frame is a combination of two equilateral triangles ACD and CDE of side 1 m. It is placed in uniform magnetic field B=4T acting perpendicular to the plane of frame. The magnitude of magnetic force acting on the frame is

Let current i=2A be flowing in each part of a wire frame as shown in Fig. 1.138. The frame is a combination of two equilateral triangles ACD and CDE of side 1 m. It is placed in uniform magnetic field B=4T acting perpendicular to the plane of frame. The magnitude of magnetic force acting on the frame is

An electron is accelerated from rest through a potential difference V. This electron experiences a force F in a uniform magnetic field. On increasing the potential difference to V' the force experienced by the electron in the same magnetic field becomes 2F. Then the ratio (V'/V) is equal to