Question Answers

Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > Length of horizontal arm of a uniform cross section U-tube is l = 1 m and ends of both of the vertical arms are open to surrounding of pressure 10^5 N/m^2 . A liquid of density ρ = 10^3 kg/m^3 is poured into the tube such that liquid just fills the horizontal part of the tube. Now one of the open ends is sealed and the tube is then rotated about a vertical axis passing through the other vertical arm With angular velocity ω0 = root 40 /3 rad/s. If length of each vertical arm is a = 1 m, calculate the length of air column in the sealed arm. (in cm)

Length of horizontal arm of a uniform cross section U-tube is l = 1 m and ends of both of the vertical arms are open to surrounding of pressure 10^5 N/m^2 . A liquid of density ρ = 10^3 kg/m^3 is poured into the tube such that liquid just fills the horizontal part of the tube. Now one of the open ends is sealed and the tube is then rotated about a vertical axis passing through the other vertical arm With angular velocity ω0 = root 40 /3 rad/s. If length of each vertical arm is a = 1 m, calculate the length of air column in the sealed arm. (in cm)

A string is holding a solid block below the surface of the liquid as shown in figure. Now if the system is given an upward constant acceleration a then as compared to previous state.