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Sahay Sir > Question Answers > Cengage JEE Mains Physics by B.M Sharma > Chapter 27 - Wave Optics > In Young’s double slit experiment d/D=10^-4. At a point P on the screen the resulting intensity is equal to the intensity due to individual slit I0. Then the distance of point P from the central maxima is ( λ=6000Å)

In Young’s double slit experiment d/D=10^-4. At a point P on the screen the resulting intensity is equal to the intensity due to individual slit I0. Then the distance of point P from the central maxima is ( λ=6000Å)

In a YDSE with identical slits the intensity at the same point is the intensity of the central bright fringe is I0. If one of the slits is covered