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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > In YDSE, light of wavelength lemda = 5000 A is used, which emerges in phase from two slits a distance d = 3 * 10^-7 m apart. A transparent sheet of thickness t = 1.5 * 10^-7 m,

In YDSE, light of wavelength lemda = 5000 A is used, which emerges in phase from two slits a distance d = 3 * 10^-7 m apart. A transparent sheet of thickness t = 1.5 * 10^-7 m,

In YDSE light of wavelength lemda = 5000 A is used which emerges in phase from two slits a distance d = 3 * 10^-7 m apart. A transparent sheet of thickness t = 1.5 * 10^-7 m