In the relation dy/dt = 2 omega sin (omega t + phi 0), the dimensional formula for omega t + phi 0 is In the relation dy/dt = 2 omega sin (omega t + phi 0) the dimensional formula for omega t + phi 0 is September 14, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) , Facebook Messenger WhatsApp Share this:TwitterFacebook Related