Question Answers

Sahay Sir > Question Answers > JEE Mains Physics 2002-2019 Solved Video Solutions > Practice Set 1 > In the given circuit of potentiometer, the potential difference E across AB (10m length) is larger than E1 and E2 as well. For key K1 (closed), the jockey is adjusted to touch the wire at point J1 so that there is no deflection in the galvanometer. Now the first battery (E1) is replaced by second battery (E2) for working by making K1 open and K2 closed. The galvanometer gives then null deflection at J2. The value of E1/E2 is a/b, where a = ___.

In the given circuit of potentiometer, the potential difference E across AB (10m length) is larger than E1 and E2 as well. For key K1 (closed), the jockey is adjusted to touch the wire at point J1 so that there is no deflection in the galvanometer. Now the first battery (E1) is replaced by second battery (E2) for working by making K1 open and K2 closed. The galvanometer gives then null deflection at J2. The value of E1/E2 is a/b, where a = ___.

In the given circuit of potentiometer The logic circuit shown above is equivalent to : the potential difference E across AB (10m length) is larger than E1 and E2 as well. For key K1 (closed)