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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > A wire of resistance 10 Ω is bent to form a circle. P and Q are points on the circumference of the circle dividing it into a quadrant and are connected to a Battery of 3 V and internal resistance 1Ω as shown in the figure. The currents in the two parts of the circle are

A wire of resistance 10 Ω is bent to form a circle. P and Q are points on the circumference of the circle dividing it into a quadrant and are connected to a Battery of 3 V and internal resistance 1Ω as shown in the figure. The currents in the two parts of the circle are

BG CD and EH. 'A' and 'C' are connected to a battery of internal resistance 'R' and emf V. Find out the current in 'AB' and 'ED'. In the figure shown eight resistors each of resistance 'R' are connected to form two squares ABCH and DEFG. Four resistors each of resistors '2R' are connected in the vertical lines AF