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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > In the configuration as shown +q charge is placed at origin and Q and Q are placed at distance a and a0 respectively from origin. If net electrostatic force on charge (+q) is along negative y-axis and θ = θ2/2, then ( Q / Q) is equal to:

In the configuration as shown +q charge is placed at origin and Q and Q are placed at distance a and a0 respectively from origin. If net electrostatic force on charge (+q) is along negative y-axis and θ = θ2/2, then ( Q / Q) is equal to:

at θ=180∘ we see that Fnet=2F0. (a) For the situation corresponding to curve 1 what is that ratio? what is the ratio of the charge of particle C to that of particle B (including sign)? (b) For the situation corresponding to curve 2