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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > In the circuit shown, R is a pure resistor, L is an inductor of negligible resistance (as compared to R) and S is a 100 V, 50 Hz AC source of negligible resistance. With eigther key k1 alone or k2 alone closed, the current is I0. if the source is changed to 100 V,100 Hz, the current with k1 alone closed and with k2 alone closed will be respectively

In the circuit shown, R is a pure resistor, L is an inductor of negligible resistance (as compared to R) and S is a 100 V, 50 Hz AC source of negligible resistance. With eigther key k1 alone or k2 alone closed, the current is I0. if the source is changed to 100 V,100 Hz, the current with k1 alone closed and with k2 alone closed will be respectively

100 Hz 50 Hz AC source of negligible resistance. With eigther key k1 alone or k2 alone closed In the circuit shown L is an inductor of negligible resistance (as compared to R) and S is a 100 V R is a pure resistor the current is I0. if the source is changed to 100 V the current with k1 alone closed and with k2 alone closed will be respectively