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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > In the circuit shown in figure, E1 and E2 are two ideal sources of unknown emfs. Some currents are shown. Potential difference appearing across 6Ω resistance is V A −V B ​ =10 V.

In the circuit shown in figure, E1 and E2 are two ideal sources of unknown emfs. Some currents are shown. Potential difference appearing across 6Ω resistance is V A −V B ​ =10 V.

E1 and E2 are two ideal sources of unknown emfs. Some currents are shown. Potential difference appearing across 6Ω resistance is V A −V B ​ =10 V. In the circuit shown in Figure