Question Answers

Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > In the above illustration, suppose there are 3.0 * 10^7 radon atoms (T 1/2 = 3.83 days or 3.31 * 10^5 s) trapped in a basement. (a) How many radon atoms remain after 31 days? (b) Find the activity

In the above illustration, suppose there are 3.0 * 10^7 radon atoms (T 1/2 = 3.83 days or 3.31 * 10^5 s) trapped in a basement. (a) How many radon atoms remain after 31 days? (b) Find the activity

In the above illustration suppose there are 3.0 * 10^7 radon atoms (T 1/2 = 3.83 days or 3.31 * 10^5 s) trapped in a basement. (a) How many radon atoms remain after 31 days? (b) Find the activity