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Sahay Sir > Question Answers > NCERT Class 10 > Maths > Chapter 6 - Triangles > In given figure from a point O in the interior of a △ABC, perpendiculars OD, OE and OF are drawn to the sides BC, CA and AB respectively. Show that : (i) AF^2 + BD^2 + CE^2 = OA^2 + OB^2 + OC^2 − OD^2 − OE^2 − OF^2 (ii) AF^2 + BD^2 + CE^2 = AE^2 + CD^2 + BF^2

In given figure from a point O in the interior of a △ABC, perpendiculars OD, OE and OF are drawn to the sides BC, CA and AB respectively. Show that : (i) AF^2 + BD^2 + CE^2 = OA^2 + OB^2 + OC^2 − OD^2 − OE^2 − OF^2 (ii) AF^2 + BD^2 + CE^2 = AE^2 + CD^2 + BF^2

CA and AB respectively. Show that : (i) AF^2 + BD^2 + CE^2 = OA^2 + OB^2 + OC^2 − OD^2 − OE^2 − OF^2 (ii) AF^2 + BD^2 + CE^2 = AE^2 + CD^2 + BF^2 In given figure from a point O in the interior of a △ABC OE and OF are drawn to the sides BC perpendiculars OD