In Fig. 6.60 , AD is a median of a triangle ABC and AM⊥BC . Prove that (i) AC^2 = AD^2 + BC⋅DM + (2/BC)^2 AD is a median of a triangle ABC and AM⊥BC . Prove that (i) AC^2 = AD^2 + BC⋅DM + (2/BC)^2 In Fig. 6.60 October 5, 2020 Category: Chapter 6 - Triangles , Maths , NCERT Class 10 , Facebook Messenger WhatsApp Share this:TwitterFacebook Related
