In Fig. 6.59, ABC is a triangle in which ∠ ABC < 90° and AD ⊥ BC. Prove that AC^2 = AB^2 + BC^2 – 2 BC . BD. ABC is a triangle in which ∠ ABC < 90° and AD ⊥ BC. Prove that AC^2 = AB^2 + BC^2 – 2 BC . BD. In Fig. 6.59 October 5, 2020 Category: Chapter 6 - Triangles , Maths , NCERT Class 10 , Facebook Messenger WhatsApp Share this:TwitterFacebook Related
