In a Young’s double slit experiment the intensity at a point where the path difference is 6/λ (λ being the wavelength of the light used) is I. if I0 denotes the maximum intensity, then I/I0 is equal to In a Young's double slit experiment the intensity at a point where the path difference is 6/λ (λ being the wavelength of the light used) is I. if I0 denotes the maximum intensity then I/I0 is equal to November 18, 2020 Category: Chapter 16 - Optics , JEE Mains Physics 2002-2019 Solved Video Solutions , Facebook Messenger WhatsApp Share this:TwitterFacebook Related