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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > In a YDSE D = 1 m, d = 1 mm, and lemda = 1/2 mm. (a) Find the distance between the first and central maxima on the screen. (b) Find the number of maxima and minima obtained on the screen.

In a YDSE D = 1 m, d = 1 mm, and lemda = 1/2 mm. (a) Find the distance between the first and central maxima on the screen. (b) Find the number of maxima and minima obtained on the screen.

and lemda = 1/2 mm. (a) Find the distance between the first and central maxima on the screen. (b) Find the number of maxima and minima obtained on the screen. d = 1 mm In a YDSE D = 1 m