In a photocell, with excitation wavelength lemda, the faster electron has speed v. If the excitation wavelength is changed to 3 lemda /4, the speed of the fastest electron will be In a photocell the faster electron has speed v. If the excitation wavelength is changed to 3 lemda /4 the speed of the fastest electron will be with excitation wavelength lemda October 12, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) , Facebook Messenger WhatsApp Share this:TwitterFacebook Related