In a Frank-Hertz experiment, an electron of energy 5.6 eV passes through mercury vapour and emerges with an energy 0.7 eV. The minimum wavelength of photons emitted by mercury atoms is close to an electron of energy 5.6 eV passes through mercury vapour and emerges with an energy 0.7 eV. The minimum wavelength of photons emitted by mercury atoms is close to In a Frank-Hertz experiment November 29, 2020 Category: Chapter 17 - Dual Nature of Radiation , JEE Mains Physics 2002-2019 Solved Video Solutions , Facebook Messenger WhatsApp Share this:TwitterFacebook Related