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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > In a car race on straight road, car A takes a times t less than car B at the finish and passes finishing point with a speed ‘v’ more than that of car B. Both the car start from rest and travel with constant acceleration a 1 ​and a 2 respectively. Then ‘v’ is equal to

In a car race on straight road, car A takes a times t less than car B at the finish and passes finishing point with a speed ‘v’ more than that of car B. Both the car start from rest and travel with constant acceleration a 1 ​and a 2 respectively. Then ‘v’ is equal to

A particle moves from the point (2.0 i+40 j^)m At t=0 In a car race on straight road the angle that the pendulum makes with the vertical is : (take g=10 m/s 2 ). The bob of a simple pendulum has mass 2g and a charge of 5.0μC. It is at rest in a uniform horizontal electric field of intensity 2000 V/m. At equilibrium