Question Answers

Sahay Sir > Question Answers > JEE Adv and Mains Chemistry 41 Years Solved Video Solutions 1979 - 2019 > Chemistry > Chapter 7 - Equilibrium > In 1 L saturated solution of AgCl [Ksp(AgCl) = 1.6 × 10^−10] 0.1 mol of CuCl [Ksp(CuCl) = 1.0 × 10^−6] is added. The resultant concentration of Ag+ in the solution is 1.6×10^−x. The value of “x” is

In 1 L saturated solution of AgCl [Ksp(AgCl) = 1.6 × 10^−10] 0.1 mol of CuCl [Ksp(CuCl) = 1.0 × 10^−6] is added. The resultant concentration of Ag+ in the solution is 1.6×10^−x. The value of “x” is

In 1 L saturated solution of AgCl [Ksp(AgCl) = 1.6 × 10^−10] 0.1 mol of CuCl [Ksp(CuCl) = 1.0 × 10^−6] is added. The resultant concentration of Ag+ in the solution is 1.6×10^−x. The value of "x" is