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Sahay Sir > Question Answers > JEE Mains Physics 2002-2019 Solved Video Solutions > Chapter 15 - Electromagnetic Waves > If the magnetic field of a plane electromagnetic wave is given by (The speed of light = 3×10^8 m/s ) B=100×10^−6sin[2π×2×10^15(t−x/c)] then the maximum electric field associated with it is :

If the magnetic field of a plane electromagnetic wave is given by (The speed of light = 3×10^8 m/s ) B=100×10^−6sin[2π×2×10^15(t−x/c)] then the maximum electric field associated with it is :

If the magnetic field of a plane electromagnetic wave is given by (The speed of light = 3×10^8 m/s ) B=100×10^−6sin[2π×2×10^15(t−x/c)] then the maximum electric field associated with it is :