Question Answers

Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > If the equation for the displacement of a particle moving on a circular path is given by (θ)=2t^3 + 0.5, where θ is in radians and t in seconds, then the angular velocity of the particle after 2s from its start is?

If the equation for the displacement of a particle moving on a circular path is given by (θ)=2t^3 + 0.5, where θ is in radians and t in seconds, then the angular velocity of the particle after 2s from its start is?

If the equation for the displacement of a particle moving on a circular path is given by (θ)=2t^3 + 0.5 then the angular velocity of the particle after 2s from its start is? where θ is in radians and t in seconds