If the energy released in the fission of one nucleus is 200 Me V. Then the number of nuclei required per second in a power plant of 16 KW will be If the energy released in the fission of one nucleus is 200 Me V. Then the number of nuclei required per second in a power plant of 16 KW will be September 15, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) , Facebook Messenger WhatsApp Share this:TwitterFacebook Related