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Sahay Sir > Question Answers > JEE Mains Physics 2002-2019 Solved Video Solutions > Chapter 17 - Dual Nature of Radiation > If the de-Broglie wavelength of an electron is equal to 10^–3 times the wavelength of a photon of frequency 6 × 10^14 Hz then the speed of electron is equal to : Speed of light = 3 × 10^8 m/s Planck’s constant = 6.63 × 10^–34 J.s Mass of electron = 9.1 × 10^–31 kg

If the de-Broglie wavelength of an electron is equal to 10^–3 times the wavelength of a photon of frequency 6 × 10^14 Hz then the speed of electron is equal to : Speed of light = 3 × 10^8 m/s Planck’s constant = 6.63 × 10^–34 J.s Mass of electron = 9.1 × 10^–31 kg

A 2 mW laser operates at a wavelength of 500 nm. The number of photons that will be emitted per second is : [Given Planck's constant h=6.6×10^−34Js speed of light c=3.0×10^8 m/s]