If the binding energy per nucleon in 73 Li and 42 He nuclear is 5.60 MeV and 7.06 MeV respectively, then in the reaction P + 73 Li → 2(42 He) energy of Proton must be If the binding energy per nucleon in 73 Li and 42 He nuclear is 5.60 MeV and 7.06 MeV respectively then in the reaction P + 73 Li → 2(42 He) energy of Proton must be November 28, 2020 Category: Chapter 18 - Atoms and Nuclei , JEE Mains Physics 2002-2019 Solved Video Solutions , Facebook Messenger WhatsApp Share this:TwitterFacebook Related