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Sahay Sir > Question Answers > MTG NEET Physics > Part 2 > Chapter 11 - Dual Nature of Radiation and Matter > If e/m of electron is 1⋅76×10^11Ckg^−1 and the stopping potential is 2.43 V, then the maximum velocity of the photoelectron is

If e/m of electron is 1⋅76×10^11Ckg^−1 and the stopping potential is 2.43 V, then the maximum velocity of the photoelectron is

If e/m of electron is 1⋅76×10^11Ckg^−1 and the stopping potential is 2.43 V then the maximum velocity of the photoelectron is