If an average person jogs, he produces 14.5 × 10^3 cal per minute. This is removed by the evaporation of sweat. The amount of sweat evaporated per minute (assuming 1 kg requires 580 × 10^3 cal for evaporation) is he produces 14.5 × 10^3 cal per minute. This is removed by the evaporation of sweat. The amount of sweat evaporated per minute (assuming 1 kg requires 580 × 10^3 cal for evaporation) is If an average person jogs September 13, 2021 Category: Chapter 11 - Thermodynamics , NCERT Exemplar Class 11 , Physics , Facebook Messenger WhatsApp Share this:TwitterFacebook Related