If a simple harmonic oscillator has got a displacement of 0.02 m and acceleration equal to 2.0 m/s^2 at any time, the angular frequency of the oscillator is equal to

- August 25, 2020
- Category: Chapter 15 - SHM , NEET Last 32 Years Solved 1988 - 2019 Physics and Chemistry Video Solutions , Physics ,
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The potential energy of a simple harmonic oscillator of mass 2 kg in its mean position is 5J. If its total energy is 9J and its amplitude is 0.01 m, its time period would be
A particle of mass (m) is attached to a spring (of spring constant k) and has a natural angular frequency omega_(0). An external force R(t) proportional to cos omega t(omega!=omega)(0) is applied to the oscillator. The time displacement of the oscillator will be proportional to.
The phase space diagram for simple harmonic motion is a circle centered at the origin. In the figure, the two circles represent the same oscillator but for different initial represent the same oscillator but for different initial conditions , and E1 and E2 are the total mechanical energies respectively. Then,
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