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Sahay Sir > Question Answers > JEE Mains Physics 2002-2019 Solved Video Solutions > Practice Set 1 > If a semiconductor photodiode can detect a photon with a maximum wavelength of 400 nm, then its band gap energy is (Planck’s constant h = 6.63 × 10^–34 J.s. Speed of light c = 3 × 10^8 m/s )

If a semiconductor photodiode can detect a photon with a maximum wavelength of 400 nm, then its band gap energy is (Planck’s constant h = 6.63 × 10^–34 J.s. Speed of light c = 3 × 10^8 m/s )

If a semiconductor photodiode can detect a photon with a maximum wavelength of 400 nm then its band gap energy is (Planck’s constant h = 6.63 × 10^–34 J.s. Speed of light c = 3 × 10^8 m/s )