If 60% of a first order reaction was completed in 60 minutes, 50% of the same reaction would be completed in approximately: (log 4 = 0.60, log 5 = 0.69). 50% of the same reaction would be completed in approximately: (log 4 = 0.60 If 60% of a first order reaction was completed in 60 minutes log 5 = 0.69). June 26, 2021 Category: Chapter 17 - Chemical Kinetics , Chemistry , NEET Last 32 Years Solved 1988 - 2019 Physics and Chemistry Video Solutions , Facebook Messenger WhatsApp Share this:TwitterFacebook Related