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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > If 200 Me v energy is released in the fission of a single U^235, the number of fission required per second to produce 1 kilowatt power shall be ( Given 1 eV = 1.6 x 10^-19 J )

If 200 Me v energy is released in the fission of a single U^235, the number of fission required per second to produce 1 kilowatt power shall be ( Given 1 eV = 1.6 x 10^-19 J )

If 200 Me v energy is released in the fission of a single U^235 the number of fission required per second to produce 1 kilowatt power shall be ( Given 1 eV = 1.6 x 10^-19 J )