How many grams of ice at −14∘C are needed to cool 200 gram of water from 25∘C to 10∘C? Take specific heat of ice =0.5 calg^−1∘C^−1 and latant heat of fusion of ice = 80 calg^−1. How many grams of ice at −14∘C are needed to cool 200 gram of water from 25∘C to 10∘C? Take specific heat of ice =0.5 calg^−1∘C^−1 and latant heat of fusion of ice = 80 calg^−1. November 19, 2020 Category: Chapter 16 - Calorimetry and Heat Transfer , MTG NEET Physics , Part 1 , Facebook Messenger WhatsApp Share this:TwitterFacebook Related