Given that x1 = 5 sin omega t x2 = 5 sin (omega t + 53) x3 = -10 cos omega t Find amplitude of resultant SHM. Given that x1 = 5 sin omega t x2 = 5 sin (omega t + 53) x3 = -10 cos omega t Find amplitude of resultant SHM. October 30, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) , Facebook Messenger WhatsApp Share this:TwitterFacebook Related
