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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > Given: mass number of gold = 197, density of gold = 19.7 g/cm^2, Avogadro’s number = 6 * 10^23. The radius of the gold atom is approximately:

Given: mass number of gold = 197, density of gold = 19.7 g/cm^2, Avogadro’s number = 6 * 10^23. The radius of the gold atom is approximately:

Avogadro's number = 6 * 10^23. The radius of the gold atom is approximately: density of gold = 19.7 g/cm^2 Given: mass number of gold = 197