Given Ka values of 5.76×10^−10 and 4.8×10^−10 for NH+4 and HCN respectively. What is the equilibrium constant for the following reaction? NH+4(aq.)+CN−(aq.)⇔NH3(aq.)+HCN(aq.) Given Ka values of 5.76×10^−10 and 4.8×10^−10 for NH+4 and HCN respectively. What is the equilibrium constant for the following reaction? NH+4(aq.)+CN−(aq.)⇔NH3(aq.)+HCN(aq.) November 12, 2020 Category: Chapter 6 - Ionic Equilibrium (Level 1 and Level 2) , N Awasthi Physical Chemistry , Facebook Messenger WhatsApp Share this:TwitterFacebook Related