Given k1 = 1500 N/m, k2 = 500 N/m, m1 = 2 kg, m2 = 1 kg. Find: a. potential energy stored in the springs in equilibrium, and b. work done in slowly pulling down m2 by 8 cm. and b. work done in slowly pulling down m2 by 8 cm. Given k1 = 1500 N/m k2 = 500 N/m m1 = 2 kg m2 = 1 kg. Find: a. potential energy stored in the springs in equilibrium October 3, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) , Facebook Messenger WhatsApp Share this:TwitterFacebook Related