Question Answers

Sahay Sir > Question Answers > MTG NEET Physics > Part 1 > Chapter 9 - Rotation > From a circular ring of mass M and radius R, an arc corresponding to a 90^∘ sector is removed. The moment of inertia of the remaining part of the ring about an axis passing through the centre of the ring and perpendicular to the plane of the ring is k times MR^2. Then the value of k is

From a circular ring of mass M and radius R, an arc corresponding to a 90^∘ sector is removed. The moment of inertia of the remaining part of the ring about an axis passing through the centre of the ring and perpendicular to the plane of the ring is k times MR^2. Then the value of k is

1) is: A force of -F k acts on O From a circular ring of mass M and radius R the origin of the coordinate system. The torque about the point (1