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Sahay Sir > Question Answers > Cengage JEE Mains Physics by B.M Sharma > Chapter 17 - Electric Charge and Field > Force between two identical charges placed at a distance of r in vacuum is F. Now a slab of dielectric constant K = 4 is inserted between these two charges . If the thickness of the slab is r/2, then the force between the charges will becomes

Force between two identical charges placed at a distance of r in vacuum is F. Now a slab of dielectric constant K = 4 is inserted between these two charges . If the thickness of the slab is r/2, then the force between the charges will becomes

Force between two identical charges placed at a distance of r in vacuum is F. Now a slab of dielectric constant K = 4 is inserted between these two charges . If the thickness of the slab is r/2 then the force between the charges will becomes