Force acting on a block moving along x-axis is given by F=−(4x^2+2)N The block is displaced from x=−2m to x=+4m, the work done will be Force acting on a block moving along x-axis is given by F=−(4x^2+2)N The block is displaced from x=−2m to x=+4m the work done will be............ October 19, 2020 Category: Arihant Physics by D.C Pandey , Chapter 6 - Work, Energy and Power , Volume 2 , Facebook Messenger WhatsApp Share this:TwitterFacebook Related